import numpy as np l1 = [1,2,3,4,5,6,7] l2 = [1,12,3,"a","b",[True,None,[True,False]],[1,2,3,[1,2,3],5,6,[15,7,9,[5,6,7]]]] # Try to find value 15 in l2 print(l2[6][6][0]) l3 = [1+1,3,[5,7,[9,8,[7,[True,99],None],6],11+12],7,9] # List can contain expressions. # Try to find 99 in l3 print(l3[2][2][2][1][1]) # Use list as function name. a is an element expression of label reference to address in Ram def a(): print("hello") l4 = [1+1,a,[3,7,[9,8,[7,[True,99],None],6],11+12],7,9] l5 = [1+1,a(),[3,7,[9,8,[7,[True,99],None],6],11+12],7,9] l4[1]() print(l4[1]) print(l5[1]) # Pop and append method # The pop() method removes the element at the specified position. Default remove the last item on the right. print(l4.pop()) print(l4.append("hello")) print(l4) # Reverse li = [1,2,3,4,5] l6 = li[1:4] # List comprehension start from 2 to 4. print(l6) l6.reverse() print(l6) # Strings s = 'hello' print(s[1]) print(s[0:4]) #s[0]="H" #Error because string is immuable. It only can be replace s = "Hello" + "world" print(s) s = "hello" s = "Hello".join("world") print(s) s = " ".join(["hello","world"]) print(s) s = "Hello World!" t = s[0:7] # It will extract position of text from 0 to 6 s = t[0] + s print(s,t)