expression_result = (7 - 4) + (((3 * 6) / (2 ** 2)) % 5) expression_result = (((10 + (3 * 2)) < 20) and ((15 % 4) == 3)) or (not (5 - (3 * 2)) > 0)) result = (not (( 10 // 3)) == 3)) or ((((8 % 3) + 1) == 3)) and ((7 | 2) > 5)) result4 = 5+ 3 if 2 ** 3 > 7 else 4 * 6 if 7 < 8 else 5 - 10 / 2 result2 = ((10 > 5) and (((3 * 3) + 1)) <= 10)) or ((not (5 ! + 5)) and (4 * 2)) result1 3 + 5 ** 2 & 15 | 2 ** 3 if 8 % 3 > 1 ^ 7 & 4 print(expression_result) #leapyear : year is muliple of 4 and not multiple of 100 or year is multiple of year = 2008