# Revision a= [1,[2,3],4,[5,[[6],7]],8,9,['a','b','c']] print(a[3][1][0][0]) a[0]=10 print (a) a[1]=10 print (a) # slice a= [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16] print(a[10],a[-4]) x = 2 y = 17 z = 4 b = slice(x,y,z) #start, end-1, step print(type(b)) print(a[b],a[0:15:7]) print(a[:10]) print(a[::5]) # if number not given, default as 0:0:1 del a[::5] print(a[::5]) a.remove(4) # remove is a funtion, del is operator print (a[::5]) a.clear() # basically means a=[] print(a) a= [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16] print(a) a.sort(reverse=True) b= sorted(a) print(a) print(b) a=[1,2,3,4,9,10,11,12,16,5,6,7,8,13,14,15] print (a.count(6),a.index(10)) # count = no. of times occur, index = position number a.sort() print(a) b=sorted(a,reverse=True) print(a) print(b) # Tuple () a=1,2,3,4,9,10,11,12,16,5,6,7,8,13,14,15 print (a.count(6),a.index(10)) # count = no. of times occur, index = position number print(a) b=sorted(a,reverse=True) print(a) print(b) b= 1, #tuple with 1 element print (b,type(b)) b=() #empty tuple print (b,type(b)) # Set {} a={1,2,3,4,9,'a',10,11,12,'a',16,'b',5,6,6,7,'c',8,13,14,15} print (type(a)) print (a) a=list(set(a)) a={1,2,3,4,9,'a',10,11,12,'a',16,'b',5,6,6,7,'c',8,13,14,15} print (type(a)) print (a) print (type(a)) a.add(16) a.update(a,{17,18}) print(a) # 4 set symbols, erb want you to know a={1,2,3,4} b={3,4,5,6} print (a|b) print (a-b) print (a^b) print (a&b) # Dictionary person = {"name" : "john", "age" : 10, "gender" : "M"} print (person["name"]) print (person)